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19 Dec 2024, 22:53
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Initial Mixture A/C = 1:3 , i.e A/C = 3 lit / 9 lit.
New Mixture A/C = 3/1 , i.e 9 lit/ 3 lit
So by using ans choices if we remove 8 lit of mixture from initial one , A/C = 1lit/3 lit replacing it with pure apple juice of 8 lit , A/C = 9 lit/3 lit i.e. 3:1 .
New Mixture A/C = 3/1 , i.e 9 lit/ 3 lit
So by using ans choices if we remove 8 lit of mixture from initial one , A/C = 1lit/3 lit replacing it with pure apple juice of 8 lit , A/C = 9 lit/3 lit i.e. 3:1 .
19 Dec 2024, 23:18
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a/c=1/3. x+3x=12-> x=3. There is a 3-liter apple juice. We should replace some amount of mixture by adding apple juice so that the result a1/c1=3/1. 3y+y=12. y=3. There is 9 litres of apple juice. How many litres are added: 9-3=6 C
19 Dec 2024, 23:32
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A 12-liter mixture of apple juice and carrot juice contains apple juice and carrot juice in a 1:3 ratio by volume. What amount of the mixture, by volume, should be replaced with an equal amount of apple juice to change the ratio of apple juice to carrot juice to 3:1 by volume ?
A. 3
B. 4
C. 6
D. 8
E. 10
From the given ratio, we know that \(a=\frac{1}{4}*12=3l\), and \(c=\frac{3}{4}*12=9l\)
As we're replacing the liquid, the final volume will remain at 12. Then, with the new proportion, we will need \(\frac{3}{(1+3)}*12 = \frac{3}{4} *12=9l\) of apple juice, and therefore just \(3 \) litres of carrot juice.
How do we get from 9l of carrot juice to just 3l? We need to get rid of the amount of liquid containing 6l of carrot juice, which constitutes 3/4 of the mixture at all times.
Hence,\(\frac{ 6}{0.75}=8l\)
So, by replacing 8 litres, we get rid of 6l of carrot juice and therefore arrive at the necessary \(9:3=a:c \) proportion. The answer is D.
A. 3
B. 4
C. 6
D. 8
E. 10
From the given ratio, we know that \(a=\frac{1}{4}*12=3l\), and \(c=\frac{3}{4}*12=9l\)
As we're replacing the liquid, the final volume will remain at 12. Then, with the new proportion, we will need \(\frac{3}{(1+3)}*12 = \frac{3}{4} *12=9l\) of apple juice, and therefore just \(3 \) litres of carrot juice.
How do we get from 9l of carrot juice to just 3l? We need to get rid of the amount of liquid containing 6l of carrot juice, which constitutes 3/4 of the mixture at all times.
Hence,\(\frac{ 6}{0.75}=8l\)
So, by replacing 8 litres, we get rid of 6l of carrot juice and therefore arrive at the necessary \(9:3=a:c \) proportion. The answer is D.
