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149 of Ferterias employees are on leave. Each emplo 12 Mar 2026, 14:26
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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45% (medium)

Question Stats:

82% (02:56) correct 18% (02:38) wrong based on 22 sessions

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149 of Ferteria’s employees are on leave. Each employee is on exactly one of the following types of leave: sick leave, maternity leave, or educational leave. Four times as many employees are on sick leave as on maternity leave. The number of employees on educational leave is 5 greater than the number on maternity leave.

If half of the employees on maternity leave and one third of the employees on sick leave return to work, how many employees will remain on leave?

A. 93
B. 100
C. 105
D. 117
E. 120
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C
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149 of Ferterias employees are on leave. Each emplo 12 Mar 2026, 15:05
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Found it hard to do in under 2 minutes tbh
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149 of Ferterias employees are on leave. Each emplo 13 Mar 2026, 00:38
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kevincan
149 of Ferteria’s employees are on leave. Each employee is on exactly one of the following types of leave: sick leave, maternity leave, or educational leave. Four times as many employees are on sick leave as on maternity leave. The number of employees on educational leave is 5 greater than the number on maternity leave.

If half of the employees on maternity leave and one third of the employees on sick leave return to work, how many employees will remain on leave?

A. 93
B. 100
C. 105
D. 117
E. 120
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Total employees on leave = 149

The ratio of sick leave to maternity leave = 4:1 = 4x : x

The number of employees on educational leave = x+5

So, the total = 4x + x + x+5 = 6x+5 = 149

x = 24

Number of sick leave : Maternity leave : Educational leave = 96 : 24 : 29

People who returned to work :

For sick leave = (1/3)* 96 = 32.

So, number of sick leave employees still on leave = 96-32 = 64

Maternity leave = (1/2)*24 = 12.

So, the number of maternity leave employees still on leave = 24 - 12 = 12.

Number of employees currently on leave = 64 + 12 + 29 = 105

Option C
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149 of Ferterias employees are on leave. Each emplo 13 Mar 2026, 09:59
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Let's break this down step by step.

Step 1: Set up variables.
Let m = employees on maternity leave.
Then:
- Sick leave = 4m (four times maternity)
- Educational leave = m + 5 (five more than maternity)

Step 2: Find m.
All three types add up to 149:
m + 4m + (m + 5) = 149
6m + 5 = 149
6m = 144
m = 24

So:
- Maternity leave: 24
- Sick leave: 4 × 24 = 96
- Educational leave: 24 + 5 = 29

Quick check: 24 + 96 + 29 = 149 ✓

Step 3: Figure out how many return to work.
- Half of maternity leave return: 24 ÷ 2 = 12 return
- One third of sick leave return: 96 ÷ 3 = 32 return
- Educational leave: nobody returns (not mentioned)

Total returning = 12 + 32 = 44

Step 4: Employees still on leave.
149 - 44 = 105

Answer: C

The most common mistake here is misreading "half return" as "half remain" or mixing up which fraction applies to which group. Always re-read the question to confirm what's returning vs. what's remaining.
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