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Re: (2^(1/2) + 5^(1/)^2. Which of the following is the best approximation? [#permalink]
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Its (a+b)^2 formula..

(\sqrt{2}+\sqrt{5})^2 = 2 + 5 + 2*\sqrt{2}*\sqrt{5}

7+ 2*\sqrt{10} = 7 + (~6) ~=13.
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Re: (2^(1/2) + 5^(1/)^2. Which of the following is the best approximation? [#permalink]
Expert Reply
IanSolo wrote:
\((\sqrt{2}+\sqrt{5})^2\) which of the following is the best approximation?

A. 7
B. 10
C. 13
D. 15
E. 17

Is there somebody who could explain how to make this calculate quickly?
I find this question in the Gmat prep software, what is the level of the question?


Solution:

(√2 + √5)^2 = 2 + 5 + 2√2√5 = 7 + 2√10

Since √10 ≈ 3, the given expression is thus approximately 7 + 2(3) = 13.

Answer: C
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Re: (2^(1/2) + 5^(1/)^2. Which of the following is the best approximation? [#permalink]
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Bunuel wrote:
IanSolo wrote:
\((\sqrt{2}+\sqrt{5})^2\) which of the following is the best approximation?
a. 7
b. 10
c. 13
d. 15
e. 17

The right answer is c.
Is there somebody who could explain how to make this calculate quickly?
I find this question in the Gmat prep software, what is the level of the question?


\((a+b)^2=a^2+2ab+b^2\), thus \((\sqrt{2}+\sqrt{5})^2=2+2*\sqrt{2}*\sqrt{5}+5=7+2\sqrt{10}\).

Now, \(3^2=9\), so \(\sqrt{10}\) is a little bit greater than 3, which means that \(7+2\sqrt{10}\approx{7+2*3}=13\).

Answer: C.

P.S. I'd say it's ~600 level question.


I unfortunately selected D :(

I saw that it was over C and thus thought -- well it must be D

Just wondering -- how large would the number be IN the square root before you still asking yourself -- should i check if i am closer to 13 or closer to 15 ?

Thank you !
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Re: (2^(1/2) + 5^(1/)^2. Which of the following is the best approximation? [#permalink]
jabhatta2 wrote:
Bunuel wrote:
IanSolo wrote:
\((\sqrt{2}+\sqrt{5})^2\) which of the following is the best approximation?
a. 7
b. 10
c. 13
d. 15
e. 17

The right answer is c.
Is there somebody who could explain how to make this calculate quickly?
I find this question in the Gmat prep software, what is the level of the question?


\((a+b)^2=a^2+2ab+b^2\), thus \((\sqrt{2}+\sqrt{5})^2=2+2*\sqrt{2}*\sqrt{5}+5=7+2\sqrt{10}\).


scottTargetTestPrep, I have the same query!!
Now, \(3^2=9\), so \(\sqrt{10}\) is a little bit greater than 3, which means that \(7+2\sqrt{10}\approx{7+2*3}=13\).

Answer: C.

P.S. I'd say it's ~600 level question.


I unfortunately selected D :(

I saw that it was over C and thus thought -- well it must be D

Just wondering -- how large would the number be IN the square root before you still asking yourself -- should i check if i am closer to 13 or closer to 15 ?

Thank you !


scott I have the same query! How does one decide to jump to the next number / what is the best approximate?
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Re: (2^(1/2) + 5^(1/)^2. Which of the following is the best approximation? [#permalink]
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