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04 Jul 2022, 14:45
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04 Jul 2022, 15:45
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2^16 = 16^4 = (17-1)^4 = I.
After Expanding I, we will get 4 terms out of which one will be +1. Rest of the three will have 17 as common. So choice C.
After Expanding I, we will get 4 terms out of which one will be +1. Rest of the three will have 17 as common. So choice C.
05 Jul 2022, 13:53
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Bunuel
2^16 – 1 is divisible by:
(A) 11
(B) 13
(C) 17
(D) 19
(E) 21
(A) 11
(B) 13
(C) 17
(D) 19
(E) 21
(2^16 – 1) = (2^8 - 1) (2^8 + 1) = (2^4 - 1) (2^4 + 1) (2^8 + 1) = 15*17*257
So amongst the options, it is divisible by 17
Answer - C
