(2^3 - 1)(2^3 + 1)(2^6 + 1)(2^12 + 1) =

Question

(2^3-1)(2^3+1)(2^6+1)(2^{12}+1)=

A.  (2^{24} -1)

B.  (2^{24} +1)

C.  (2^{48} -1)

D.  (2^{96} +1)

E.  2^6(2^{12} -1)

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ajaynandakumar7 · Answer

Solving the first 2 terms for a^2-b^2 will give the third term and again applying the same logic will yield option A

Ayeka · Answer

(2^3 - 1)(2^3 + 1)(2^6 + 1)(2^12 + 1)
  (2^6 + 1)(2^12 + 1)
(2^6 -1) (2^6 + 1)(2^12 + 1)
(2^12 -1)(2^12 +1)
(2^24 -1)

Answer: A

AVMachine · Answer

A^2 - B^2 = (A+B) (A-B)

(2^3 - 1)(2^3 + 1) = (2^6 - 1)
(2^6 - 1)(2^6 + 1) = (2^12 - 1)
(2^12 - 1)(2^12 + 1) = (2^24 - 1)

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