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# 2 + 2 + 2^2 + 2^3 + 2^4 + 2^6 + 2^7 + 2^8 =

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Intern
Joined: 01 Dec 2008
Posts: 8
2 + 2 + 2^2 + 2^3 + 2^4 + 2^6 + 2^7 + 2^8 =  [#permalink]

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04 Jan 2009, 00:50
$$2 + 2 + 2^2 + 2^3 + 2^4 + 2^6 + 2^7 + 2^8 =$$

(A) $$2^9$$
(B) $$2^1^0$$
(C) $$2^1^6$$
(D) $$2^3^5$$
(E) $$2^3^7$$

Is there a method to solve this kind of equation fast? I got it from GMATPrep.

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SVP
Joined: 29 Aug 2007
Posts: 2419

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04 Jan 2009, 15:28
georgechanhc wrote:

Is there a method to solve this kind of equation fast? I got it from GMATPrep.

Discussed here: http://gmatclub.com/forum/7-t74231

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

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Re: GmatPrep Q &nbs [#permalink] 04 Jan 2009, 15:28
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# 2 + 2 + 2^2 + 2^3 + 2^4 + 2^6 + 2^7 + 2^8 =

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