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02 Aug 2022, 02:45
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
69% (02:55) correct
31%
(02:43)
wrong
based on 228
sessions
History
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Not Attempted Yet
2 men and 7 boys can do a piece of work in 14 days; 3 men and 8 boys can do the same in 11 days. Then, 8 men and 6 boys can do three times the amount of this work in :
(A) 18 days
(B) 21 days
(C) 24 days
(D) 30 days
(E) 31 days
(A) 18 days
(B) 21 days
(C) 24 days
(D) 30 days
(E) 31 days
02 Aug 2022, 03:02
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here
Boys per day work=b
Men per day work=m
Condition 1
Total work 14(2m+7b)
Condition 2
Total work 11(3m+8b)
from 1 and 2
28m-33m=88b-98b
5m=10b
m=2b
Condition 1
Total work 14(11b)
What we have to find
33(14b)=X(16b+6b)
X=21 days
Boys per day work=b
Men per day work=m
Condition 1
Total work 14(2m+7b)
Condition 2
Total work 11(3m+8b)
from 1 and 2
28m-33m=88b-98b
5m=10b
m=2b
Condition 1
Total work 14(11b)
What we have to find
33(14b)=X(16b+6b)
X=21 days
02 Aug 2022, 05:25
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Let the efficiency of 1 man’s work in one day be M, and that of a child be C.
Since 2 men and 7 boys can do a piece of work in 14 days,
Total work = 14(2M + 7B)
Similarly, Total work = 11(3M + 8B)
Since the total work will be the same,
14(2M + 7B) = 11(3M + 8B)
5M = 10B
M = 2B
So, the total work = 14(4B + 7B) = 154B
Work done by 8 men and 6 boys in one day = 16B + 6B = 22B
Thus, the total time taken by 8 men and 6 boys to complete three times the work = 154B*3/22B = 21
Thus, the correct answer is B.
Since 2 men and 7 boys can do a piece of work in 14 days,
Total work = 14(2M + 7B)
Similarly, Total work = 11(3M + 8B)
Since the total work will be the same,
14(2M + 7B) = 11(3M + 8B)
5M = 10B
M = 2B
So, the total work = 14(4B + 7B) = 154B
Work done by 8 men and 6 boys in one day = 16B + 6B = 22B
Thus, the total time taken by 8 men and 6 boys to complete three times the work = 154B*3/22B = 21
Thus, the correct answer is B.
