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Let us say the gardener plants 1 tree on first day and 1 tree on a second day. The he has to plant 8 trees on third day. Following are the combinations for planting 1 tree on a first day
(1,1,8)
(1,2,7)
(1,3,6)
...
...
(8,1,1)
Total 8 combinations
If he plants 2 tree on first day you get
(2,1,7)
(2,2,6)
....
(8,1,1)
Total 7 combinations
Like this you get 8+7+6+4+3+2+1 = n*(n+1)/2 = 8*9/2 = 36
Let us say the gardener plants 1 tree on first day and 1 tree on a second day. The he has to plant 8 trees on third day. Following are the combinations for planting 1 tree on a first day (1,1,8) (1,2,7) (1,3,6) ... ... (8,1,1) Total 8 combinations If he plants 2 tree on first day you get (2,1,7) (2,2,6) .... (8,1,1) Total 7 combinations
Like this you get 8+7+6+4+3+2+1 = n*(n+1)/2 = 8*9/2 = 36
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Correct. the answer is 36. good explanation
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