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30 May 2017, 20:43
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50% (01:46) correct
50%
(01:40)
wrong
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\(\frac{2}{\sqrt{16+6\sqrt{7}}}=\)
A. \(\frac{1}{127}\)
B. \(\frac{4}{16+6\sqrt{7}}\)
C. \(\frac{\sqrt{16-6\sqrt{7}}}{4}\)
D. \(\sqrt{16-6\sqrt{7}}\)
E. \(\sqrt{16+6\sqrt{7}}\)
A. \(\frac{1}{127}\)
B. \(\frac{4}{16+6\sqrt{7}}\)
C. \(\frac{\sqrt{16-6\sqrt{7}}}{4}\)
D. \(\sqrt{16-6\sqrt{7}}\)
E. \(\sqrt{16+6\sqrt{7}}\)
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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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30 May 2017, 21:01
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nguyendinhtuong
\(\frac{2}{\sqrt{16+6\sqrt{7}}}=\)
A. \(\frac{1}{127}\)
B. \(\frac{4}{16+6\sqrt{7}}\)
C. \(\frac{\sqrt{16-6\sqrt{7}}}{4}\)
D. \(\sqrt{16-6\sqrt{7}}\)
E. \(\sqrt{16+6\sqrt{7}}\)
A. \(\frac{1}{127}\)
B. \(\frac{4}{16+6\sqrt{7}}\)
C. \(\frac{\sqrt{16-6\sqrt{7}}}{4}\)
D. \(\sqrt{16-6\sqrt{7}}\)
E. \(\sqrt{16+6\sqrt{7}}\)
Check here: 2-240047.html
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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