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14 Oct 2025, 10:48
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
83% (00:36) correct
16% (00:52) wrong based on 6 sessions
History
Date
Time
Result
Not Attempted Yet
15 Oct 2025, 19:45
Kudos
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-2|x-5|= -12
|x-5| = -12/-2
|x-5| =6
-+(x-5)=6
x-5=6 ; x=6+5=11 ; x=11
-x+5=6 ; x=5-6=-1 ; x= -1
Quantity A: x= -1 or 11
Quantity B: 0
If x=-1 ; A<B
If x=11 ; A>B
D
|x-5| = -12/-2
|x-5| =6
-+(x-5)=6
x-5=6 ; x=6+5=11 ; x=11
-x+5=6 ; x=5-6=-1 ; x= -1
Quantity A: x= -1 or 11
Quantity B: 0
If x=-1 ; A<B
If x=11 ; A>B
D
18 Oct 2025, 03:49
Kudos
Bookmarks
Official Explanation
Recall that absolute value equations generally have two solutions. Divide both sides by –2 to obtain \(|x – 5| = 6.\) Therefore, \(x – 5 = 6, or x – 5 = –6.\) Adding 5 to both sides in each equation yields \(x = 11\) or \(x = –1.\) Since one possible x value is greater than 0, while the other is less than 0, there is not enough information to determine, and (D) is correct.
Answer: D
Recall that absolute value equations generally have two solutions. Divide both sides by –2 to obtain \(|x – 5| = 6.\) Therefore, \(x – 5 = 6, or x – 5 = –6.\) Adding 5 to both sides in each equation yields \(x = 11\) or \(x = –1.\) Since one possible x value is greater than 0, while the other is less than 0, there is not enough information to determine, and (D) is correct.
Answer: D
