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20 of the 80 employees at a certain organization are doctors. If two

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Math Expert
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Joined: 02 Sep 2009
Posts: 58335
20 of the 80 employees at a certain organization are doctors. If two  [#permalink]

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New post 18 Jan 2019, 00:51
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

65% (01:37) correct 35% (01:24) wrong based on 53 sessions

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Joined: 18 Aug 2017
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Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
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Re: 20 of the 80 employees at a certain organization are doctors. If two  [#permalink]

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New post 18 Jan 2019, 07:25
Bunuel wrote:
20 of the 80 employees at a certain organization are doctors. If two employees are to be selected at random, which of the following is closest to the probability that neither employee selected is a doctor?

A 0.2
B 0.4
C 0.6
D 0.7
E 0.8


not doctors = 80-20 = 60
60*59/ 80 * 70
=> ~ 0.6 IMO C
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Re: 20 of the 80 employees at a certain organization are doctors. If two  [#permalink]

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New post 18 Jan 2019, 07:46
Bunuel wrote:
20 of the 80 employees at a certain organization are doctors. If two employees are to be selected at random, which of the following is closest to the probability that neither employee selected is a doctor?

A 0.2
B 0.4
C 0.6
D 0.7
E 0.8


Now if we are selecting neither employee as a doctor this will mean we will be selecting from 60 employees

60 c 2 / 80 C 2

= 60 * 59 / 80 * 79
= 0.56
~ 0.6

Answer C
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Re: 20 of the 80 employees at a certain organization are doctors. If two  [#permalink]

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New post 18 Jan 2019, 19:42
We don't need exact, just approximate
20 of the 80 employees at a certain organization are doctors
3/4 are not doctors

two employees...probability that neither employee selected is a doctor
3/4·59/79
59/79 is basically 3/4
3/4·3/4=9/16

16·6=96 which is basically 100
9·6/16·6=54/96
96 is a bit below 100, so the answer should be a bit above 54/100

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Re: 20 of the 80 employees at a certain organization are doctors. If two   [#permalink] 18 Jan 2019, 19:42
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