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200^2 − 2(200)(199) + 199^2 =

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200^2 − 2(200)(199) + 199^2 =  [#permalink]

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New post Updated on: 06 Nov 2018, 08:58
1
4
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

78% (00:46) correct 22% (01:18) wrong based on 88 sessions

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\(200^2\) − 2(200)(199) + \(199^2\) =

(A) −79,201
(B) −200
(C) 1
(D) 200
(E) 79,999

Difficulty Level: 550

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Originally posted by SajjadAhmad on 04 Mar 2017, 11:43.
Last edited by SajjadAhmad on 06 Nov 2018, 08:58, edited 2 times in total.
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Re: 200^2 − 2(200)(199) + 199^2 =  [#permalink]

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New post 04 Mar 2017, 22:53
SajjadAhmad wrote:
200^2 − 2(200)(199) + 199^2 =

(A) −79,201
(B) −200
(C) 1
(D) 200
(E) 79,999


\(200^2 − 2(200)(199) + 199^2 = ( 200 - 199 )^2\)

( 200 - 199 )^2 = 1^2

Thus, answer must be (C) 1

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Re: 200^2 − 2(200)(199) + 199^2 =  [#permalink]

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New post 20 Oct 2018, 07:37
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Re: 200^2 − 2(200)(199) + 199^2 = &nbs [#permalink] 20 Oct 2018, 07:37
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