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hi.. one way ican think of this ques specifically is:- look at denominator it is .128 or 2^6 , so if u multiply it with 5^6 u will get 10^6/1000(as it is .128).. u will also multiply numerator with 5^6 so ans shud be a multiple of 5... as u have found ans in 190s... 195 shud be correct
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First, 0.128 is equal to 2^7/10^3. So we have \(\frac{25}{0.128} = \frac{5^2}{\frac{2^7}{(2^3)(5^3)}} = \frac{5^5}{2^4}\) There is no chance of this being an integer, so we can't use divisibility properties here; it's purely coincidental that the closest integer to this expression is a multiple of 5. You can see why there is no reason to expect a similar expression to be close to a multiple of 5 by looking at a fraction with smaller powers; for example, the fraction 5^2/2^2 is equal to 6.25, so the closest integer to 5^2/2^2 is not a multiple of 5.
The question should mention that it's asking for an approximation, since 25/0.128 is not exactly equal to any of the answer choices. If I were to need to estimate its value, I'd first get integers in the numerator and denominator:
Now we know 3200 = 16*200. 3125 is 75 less than 3200, and 75/16 is just less than 5, so 3125/16 will be just larger than 195 (it's exactly equal to 195 and 5/16ths).
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