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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
89% (00:23) correct
11%
(01:17)
wrong
based on 57
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History
Date
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\(\small \frac{\sqrt[3]{27}}{\sqrt{9}}= \)
A. \( \small 1\)
B. \(\small 2\)
C. \( \small \sqrt{3}\)
D. \(\small \sqrt[3]{3}\)
E. \(\small \frac{1}{\sqrt[6]{3}}\)
Source: GMAP Prep
A. \( \small 1\)
B. \(\small 2\)
C. \( \small \sqrt{3}\)
D. \(\small \sqrt[3]{3}\)
E. \(\small \frac{1}{\sqrt[6]{3}}\)
Source: GMAP Prep
15 Mar 2021, 18:16
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\(\sqrt[3]{27}/\sqrt{9}\)=?
27 = 3 * 3 * 3 = \(3^3\)
9 = 3 * 3 = \(3^2\)
\(\sqrt[3]{27}\) = \(\sqrt[3]{3^3}\) = \((3^3)^\frac{1}{3}\) = 3
\(\sqrt{9}\) = \(\sqrt{3^2}\) = \((3^2)^\frac{1}{2}\) = 3
=>\(\sqrt[3]{27}/\sqrt{9}\) = \(\frac{3}{3}\) = 1
So, correct answer is option A.
27 = 3 * 3 * 3 = \(3^3\)
9 = 3 * 3 = \(3^2\)
\(\sqrt[3]{27}\) = \(\sqrt[3]{3^3}\) = \((3^3)^\frac{1}{3}\) = 3
\(\sqrt{9}\) = \(\sqrt{3^2}\) = \((3^2)^\frac{1}{2}\) = 3
=>\(\sqrt[3]{27}/\sqrt{9}\) = \(\frac{3}{3}\) = 1
So, correct answer is option A.
15 Mar 2021, 22:53
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The cube root of 27 is 3 and the square root of 9 is 3.
=> \(\frac{3}{3} = 1\)
Answer A
=> \(\frac{3}{3} = 1\)
Answer A
