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E
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Difficulty:
15%
(low)
Question Stats:
82% (01:11) correct
18%
(01:07)
wrong
based on 39
sessions
History
Date
Time
Result
Not Attempted Yet
\(\frac{3}{3+ (3^{-1}+1^{-1})^{-1}} =\)
(A) 3/7
(B) 1/2
(C) 4/7
(D) 5/7
(E) 4/5
Source: https://gmatquantum.com/
(A) 3/7
(B) 1/2
(C) 4/7
(D) 5/7
(E) 4/5
Source: https://gmatquantum.com/
05 Mar 2020, 06:45
Kudos
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sjuniv32
\(\frac{3}{3+ (3^{-1}+1^{-1})^{-1}} =\)
(A) 3/7
(B) 1/2
(C) 4/7
(D) 5/7
(E) 4/5
Source: https://gmatquantum.com/
(A) 3/7
(B) 1/2
(C) 4/7
(D) 5/7
(E) 4/5
Source: https://gmatquantum.com/
\(\frac{3}{3 + (3^{-1}+1^{-1})^{-1}} = \frac{3}{3+(\frac{1}{3} + 1)^{-1}}=\frac{3}{3+(\frac{4}{3})^{-1}}=\frac{3}{3+\frac{3}{4}}=\frac{3}{\frac{15}{4}}=3*\frac{4}{15}=\frac{4}{5}\).
Answer: E.
General Discussion
05 Mar 2020, 06:23
Kudos
Bookmarks
sjuniv32
\(\frac{3}{(3^{-1}+1^{-1})^{-1}} =\)
(A) 3/7
(B) 1/2
(C) 4/7
(D) 5/7
(E) 4/5
Source: https://gmatquantum.com/
(A) 3/7
(B) 1/2
(C) 4/7
(D) 5/7
(E) 4/5
Source: https://gmatquantum.com/
\(\frac{3}{(3^{-1}+1^{-1})^{-1}} = \frac{3}{(\frac{1}{3} + 1)^{-1}}=\frac{3}{(\frac{4}{3})^{-1}}=\frac{3}{\frac{3}{4}}=3*\frac{4}{3}=4\).
Either the options are wrong or the question (formatting?).
