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4 A shipment of 8 television sets contains 2 black-and-white sets and 6color sets. If 2 television sets are to be chosen at random from this shipment, what is the probability that at least 1 of the 2 sets chosen will be a black-and-white set? A. 1/7 B. ¼ C. 5/14 D. 11/28 E. 13/26
Pls explain your answers.
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can you explain how you got 6c2 and 8c2? combination is one of my weak areas...
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seongbae ,
Here total number of choice for TV set is 8 (2 b&w ; 6 color ) , by combination logic if we have to select two TV set out of 8 , it is
8c2= 8!/(2!(8-2))!
Now if we have to find the pobability that atleast 1 TV is B&W , easier method is to find the probability of no B&W TV chosen which means 2 TV sets are chosen from 6 color TV ; by the same logic explained above , number of way we can select 2 TV out of 6 will be 6c2. And so probability of chosing 2 TV set from 6 color TV set will be 6c2/8c2 .
To get aleast one B&W TV , we simply subtract 6c2/8c2 from 1 .
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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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