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# (49^2 - 35^2)/14 =

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Study Buddy Forum Moderator
Joined: 04 Sep 2016
Posts: 1299
Location: India
WE: Engineering (Other)

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Updated on: 10 Dec 2017, 19:52
1
5
00:00

Difficulty:

5% (low)

Question Stats:

87% (01:22) correct 13% (01:57) wrong based on 92 sessions

### HideShow timer Statistics

$$\frac{(49^2 - 35^2)}{14} =$$

A. 74
B. 76
C. 78
D. 79
E. 84

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Originally posted by adkikani on 10 Dec 2017, 17:51.
Last edited by Bunuel on 10 Dec 2017, 19:52, edited 1 time in total.
Renamed the topic, edited the question
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Joined: 02 Aug 2009
Posts: 7334

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10 Dec 2017, 18:03
1
$$(49^2 - 35^2)$$ /14 =

A. 74
B. 76
C. 78
D. 79
E. 84

Ofcourse it is $$a^2-b^2=(a-b)(a+b)$$..
Here (49-35)(49+35)/14=14*84/14=84..

Do your calculations or observer the properties of number involved, of the calculations are difficult, and answer in a sec, ...

Both 49 and 35 have a 7 in them..
So we will get 7*7 in the product, one 7 from addition and other from subtraction..
One 7 gets cancelled out with 7 in 14..
Our ANSWER should be a MULTIPLE of 7..
Only E left
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1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html
4) Base while finding % increase and % decrease : https://gmatclub.com/forum/percentage-increase-decrease-what-should-be-the-denominator-287528.html

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Re: (49^2 - 35^2)/14 =  [#permalink]

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10 Dec 2017, 19:56
Top Contributor
1
$$\frac{(49^2 - 35^2)}{14} =$$

A. 74
B. 76
C. 78
D. 79
E. 84

(49² - 35²)/14 = (49 + 35)(49 - 35)/14
= (84)(14)/14
= 84
= E

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10 Dec 2017, 21:33
$$\frac{(49^2 - 35^2)}{14} =$$

A. 74
B. 76
C. 78
D. 79
E. 84

$$\frac{(49^2 - 35^2)}{14}=?$$

Start writing what you know, breaking numbers into pieces: $$49^2 = (49)(49)$$, for example. And there are factors of 7 everywhere.

Factor everything, with cancellation in mind if you can, to reduce errors.

$$\frac{(49)(49) - (35)(35)}{(2*7)}=$$

$$\frac{(7*7*7*7) - (7*5*7*5)}{(2*7)}=$$

Notice two 7s in numerator's two terms, hence

$$\frac{49(7*7 - 5*5)}{(2*7)}=$$

$$\frac{49(49 - 25)}{(2*7)}=\frac{49*(24)}{2*7}=$$

$$\frac{(7*7)(2*12)}{2*7}= (7*12) = 84$$

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Re: (49^2 - 35^2)/14 =  [#permalink]

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13 Dec 2017, 19:58
$$\frac{(49^2 - 35^2)}{14} =$$

A. 74
B. 76
C. 78
D. 79
E. 84

Responding to a pm:
Quote:
Can this be also solved using unit digits?

I am not sure what you mean. How do you intend to use unit's digit concept here?

You are probably confusing it with using units digit concept for remainders when dividing by 2, 5 or 10. Check it out here:

https://www.veritasprep.com/blog/2015/1 ... questions/
https://www.veritasprep.com/blog/2015/1 ... ns-part-2/
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Re: (49^2 - 35^2)/14 =  [#permalink]

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09 Feb 2019, 13:22
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Re: (49^2 - 35^2)/14 =   [#permalink] 09 Feb 2019, 13:22
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