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![[(n+3)!]^5/[(n+2)!]^5 =](https://cdn.gmatclub.com/cdn/files/forum/styles/gmatclub_light/imageset/icon_post_target_unread.svg "[(n+3)!]^5/[(n+2)!]^5 ="){kind=icon}
06 Jun 2017, 11:37
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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90% (00:51) correct
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\(\frac{[(n+3)!]^5}{[(n+2)!]^5} =\)
A. 2
B. (n+1)^5
C. (n+2)^5
D. (n+3)^5
E. ((n+3/(n+2))^5
A. 2
B. (n+1)^5
C. (n+2)^5
D. (n+3)^5
E. ((n+3/(n+2))^5
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Updated on: 06 Jun 2017, 13:12
Originally posted by quantumliner on 06 Jun 2017, 12:42.
Last edited by quantumliner on 06 Jun 2017, 13:12, edited 2 times in total.
Last edited by quantumliner on 06 Jun 2017, 13:12, edited 2 times in total.
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(n+3)! can be written as (n+3)(n+2)!
now \([(n+3)!]^5\) can be written as \([(n+3)(n+2)!]^5\) = \((n+3)^5\) * \([(n+2)!]^5\)
therefore
\([(n+3)!]^5\)/\([(n+2)!]^5\) = [\((n+3)^5\) *\([(n+2)!]^5\)]/\([(n+2)!]^5\) = (n+3)^5
Answer is D
now \([(n+3)!]^5\) can be written as \([(n+3)(n+2)!]^5\) = \((n+3)^5\) * \([(n+2)!]^5\)
therefore
\([(n+3)!]^5\)/\([(n+2)!]^5\) = [\((n+3)^5\) *\([(n+2)!]^5\)]/\([(n+2)!]^5\) = (n+3)^5
Answer is D
06 Jun 2017, 13:03
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quantumliner
(n+3)! can be written as (n+3)(n+2)!
now \([(n+3)!]^5\) can be written as \([(n+3)(n+2)!]^5\) = \((n+3)^5\) * \([(n+2)!]^5\)
therefore
\([(n+3)!]^5\)/\([(n+2)!]^5\) = [\((n+3)^5\) *\([(n+2)!]^5\)]/\([(n+2)!]^5\) = (n+3)^5
Answer is E
now \([(n+3)!]^5\) can be written as \([(n+3)(n+2)!]^5\) = \((n+3)^5\) * \([(n+2)!]^5\)
therefore
\([(n+3)!]^5\)/\([(n+2)!]^5\) = [\((n+3)^5\) *\([(n+2)!]^5\)]/\([(n+2)!]^5\) = (n+3)^5
Answer is E
hi quantumliner
you have got the right answer but the option mentioned by you is wrong. Suggest you rectify it.
