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19 Nov 2009, 08:32
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N
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5 different integer has average (arithmatic mean) 24, how many integers are greater than 22 ?
1) sum of the greatest two integers is 59
2) sum of least two integers is 39
Regards,
Rohit
1) sum of the greatest two integers is 59
2) sum of least two integers is 39
Regards,
Rohit
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19 Nov 2009, 08:50
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KocharRohit
C
let the 5 diff integers be a,b,c,d,e (in increasing order of value) and their sum is 120 (avg 24)
1. d,e can be 23,36/25,34 or 22,37. then a+b+c = 61
which can be 19,20,22 or 18,20,23. hence insuff
2. a,b can be 19,20 or 16,23 and also the sum of c+d+e = 81 can be obtained by 26,27,28 or 21,22,38. hence insuff
taking both we have a+b+d+e = 98 and c= 22. therefore we have 2 integers greater than 22. Suff
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