Bunuel
5 Indian & 5 American couples meet at a party and shake hands. If no wife shakes hands with her own husband and no Indian wife shakes hands with a male then the number of handshakes that takes place in the party is
(A) 95
(B) 110
(C) 135
(D) 150
(E) 160
good cases = all possible cases - bad cases
All possible cases:From 20 people, the number of ways to form a pair to shake hands = 20C2 \(= \frac{20*19}{2*1} = 190\)
Bad case 1: An Indian woman shakes hands with a maleNumber of ways to choose an Indian woman = 5
Number of ways to choose a male = 10
To combine these options, we multiply:
5*10 = 50
Bad case 2: An American woman shakes hands with her own husbandSince there are 5 American couples that could yield a wife shaking hands with her own husband, we get:
5
Thus:good cases = (all possible cases) - (bad case 1) - (bad case 2) = 190 - 50 - 5 = 135