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=>

Assume x is the number of students who solved only question \(B\) correctly.
Then we have the total average \(\frac{(10*35 + 10x)}{50} = 13\) which is equivalent to
\(350 + 10x = 650.\)

\(=> 10x = 300\)

\(=> x = 30.\)

Then the number of students who solved only question \(B\) correctly is
\(x – 20 = 30 – 20 = 10.\)

Therefore, D is the answer.
Answer: D
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MathRevolution
=>

Assume x is the number of students who solved only question \(B\) correctly.
Then we have the total average \(\frac{(10*35 + 10x)}{50} = 13\) which is equivalent to
\(350 + 10x = 650.\)

\(=> 10x = 300\)

\(=> x = 30.\)

Then the number of students who solved only question \(B\) correctly is
\(x – 20 = 30 – 20 = 10.\)

Therefore, D is the answer.
Answer: D

If you are assuming that 'x' is the number of students who solved only question B correctly then why are you subtracting 20 ? I think 'x' should be the number of students who answered B correctly and this x includes those who answered both correctly, and then it would be correct to subtract 20 from whatever value we get for 'x'.
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