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-6/(b+2) = 5/(b-9)

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Manager
Joined: 17 Jul 2010
Posts: 109

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23 Aug 2012, 07:08
00:00

Difficulty:

5% (low)

Question Stats:

92% (00:53) correct 8% (01:20) wrong based on 123 sessions

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-6(b-9)/(b+2)=5

A. 1
B. 2
C. 3
D. -4
E. 4

Can someone tell me why this turns to this, when getting rid of the denominators?
I'm not following why the variables are rewritten this way? Please explain.
Math Expert
Joined: 02 Sep 2009
Posts: 59236

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23 Aug 2012, 07:13
1
laythesmack23 wrote:
-6(b-9)/(b+2)=5

A. 1
B. 2
C. 3
D. -4
E. 4

Can someone tell me why this turns to this, when getting rid of the denominators?
I'm not following why the variables are rewritten this way? Please explain.

Multiply both parts by $$b+2$$ --> $$-6(b-9)=5(b+2)$$ --> $$-6b+54=5b+10$$ --> $$11b=44$$ --> $$b=4$$.

Hope it's clear.
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Re: -6/(b+2) = 5/(b-9)   [#permalink] 23 Aug 2012, 07:13
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