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23 Oct 2018, 21:53
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B
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Difficulty:
5%
(low)
Question Stats:
92% (00:37) correct
8%
(00:56)
wrong
based on 96
sessions
History
Date
Time
Result
Not Attempted Yet
\(9^k*27^{2k} =\)
A. \(3^{5+3k}\)
B. \(3^{8k}\)
C. \(3^{11k}\)
D. \(3^{12k}\)
E. \(3^{12k^2}\)
A. \(3^{5+3k}\)
B. \(3^{8k}\)
C. \(3^{11k}\)
D. \(3^{12k}\)
E. \(3^{12k^2}\)
eswarchethu135
23 Oct 2018, 22:29
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3^2k * 3^6k
3^(2k+6k)
3^8k
OPTION : B
3^(2k+6k)
3^8k
OPTION : B
23 Oct 2018, 23:06
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Pretty straightforward question if we remember our exponent properties.
\(((a^b)^c) = a^{bc}\)
\((a^b * a^c) = a^{b+c}\)
Applying here...
\(9^k∗27^{2k}=\)
\((3^2)^k∗(3^3)^{2k}=\)
\(3^{2k}*(3^{6k})=\)
\(3^{8k}\)
Answer B.
\(((a^b)^c) = a^{bc}\)
\((a^b * a^c) = a^{b+c}\)
Applying here...
\(9^k∗27^{2k}=\)
\((3^2)^k∗(3^3)^{2k}=\)
\(3^{2k}*(3^{6k})=\)
\(3^{8k}\)
Answer B.
