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IrinaOK
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A 28 B 29 C 31 D 32 E 33 *editted OA is B, thanks Updated on: 20 Sep 2007, 13:26
Originally posted by IrinaOK on 20 Sep 2007, 11:36.
Last edited by IrinaOK on 20 Sep 2007, 13:26, edited 1 time in total.
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A 28
B 29
C 31
D 32
E 33

*editted

OA is B, thanks.



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A 28 B 29 C 31 D 32 E 33 *editted OA is B, thanks 20 Sep 2007, 11:51
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IrinaOK
A 20
B 24
C 25
D 30
E 32
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13*15=195
12*16=192

not both, it means that we should substract 1 from 15 and 1 from 16 (1 represents 12*13). So the answer is 14+15=29????
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Ravshonbek
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A 28 B 29 C 31 D 32 E 33 *editted OA is B, thanks 20 Sep 2007, 12:05
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IrinaOK
A 20
B 24
C 25
D 30
E 32
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12*(1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16)
13*(1+2+3+4+5+6+7+8+9+10+11+12+13+14+15)
total 31

12*13=156 is out

thus 31-1=30
D
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A 28 B 29 C 31 D 32 E 33 *editted OA is B, thanks 20 Sep 2007, 12:17
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I get 29 as well.

12 has 16 multiples and 13 has 15 multiples for a total of 31 multiples. When you take out 156 from both sets you get 29???
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gixxer1000
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A 28 B 29 C 31 D 32 E 33 *editted OA is B, thanks 20 Sep 2007, 12:19
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Ravshonbek
IrinaOK
A 20
B 24
C 25
D 30
E 32


12*(1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16)
13*(1+2+3+4+5+6+7+8+9+10+11+12+13+14+15)
total 31

12*13=156 is out

thus 31-1=30
D
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12*13=156 is out
13*12=156 should be out as well
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FN
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A 28 B 29 C 31 D 32 E 33 *editted OA is B, thanks 20 Sep 2007, 13:07
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200/13 = 15

200/12=16

200/13*12=1

15+16=31-1=30.

D it is..
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Ravshonbek
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A 28 B 29 C 31 D 32 E 33 *editted OA is B, thanks 20 Sep 2007, 13:13
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gixxer1000
I get 29 as well.

12 has 16 multiples and 13 has 15 multiples for a total of 31 multiples. When you take out 156 from both sets you get 29???
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there is only one 156 among the multiples of 12 and 13 which is less than 156
so count it as one integer/number
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gixxer1000
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A 28 B 29 C 31 D 32 E 33 *editted OA is B, thanks 20 Sep 2007, 13:16
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fresinha12
200/13 = 15

200/12=16

200/13*12=1

15+16=31-1=30.

D it is..
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12(12,24,36,48,60,72,84,96,108,120,132,144,156,168,180,192) = 16 multiples

13(13,26,39,52,65,78,91,104,117,130,143,156,169,182,195) = 15 multiples

That's a total of 31 multiples.

You know have to remove 156 from BOTH sets which leave 29 multiples.
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bkk145
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A 28 B 29 C 31 D 32 E 33 *editted OA is B, thanks 20 Sep 2007, 13:29
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IrinaOK
A 28
B 29
C 31
D 32
E 33

*editted

OA is B, thanks.
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I got 29 as well...

16-1 = 15
15-1 = 14
15+14 = 29
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Ravshonbek
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A 28 B 29 C 31 D 32 E 33 *editted OA is B, thanks 20 Sep 2007, 14:45
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gixxer1000
fresinha12
200/13 = 15

200/12=16

200/13*12=1

15+16=31-1=30.

D it is..

12(12,24,36,48,60,72,84,96,108,120,132,144,156,168,180,192) = 16 multiples

13(13,26,39,52,65,78,91,104,117,130,143,156,169,182,195) = 15 multiples

That's a total of 31 multiples.

You know have to remove 156 from BOTH sets which leave 29 multiples.
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You r right, i am just trying to play around with this quesiton differently which i thought correct, i think i got the stem wrong
additional assumptions lead to that answer
thanks



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