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15 Oct 2018, 07:58
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
71% (01:51) correct
29%
(01:45)
wrong
based on 78
sessions
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A, B, and C are three unequal faces of a rectangular tank. The tank contains a certain amount of water. When the tank is based on the face A, the height of the water is half the height of the tank. The dimensions of the side B are 3 ft × 4 ft and the dimensions of side C are 4 ft × 5 ft. What is the measure of the height of the water in the tank in feet?
(A) 2
(B) 2.5
(C) 3
(D) 4
(E) 5
(A) 2
(B) 2.5
(C) 3
(D) 4
(E) 5
15 Oct 2018, 08:46
Kudos
Bookmarks
Bunuel
After resting face A as the base of the water tank, since 4 ft is common to both the faces B and C; 4 ft must be the measure of height of the tank.
So, the height of water=\(\frac{4}{2}=2\)
Ans. (A)
15 Oct 2018, 08:57
Kudos
Bookmarks
Bunuel
A, B, and C are three unequal faces of a rectangular tank ==> L!=B!=H
As on A the tank bases.... the common side of plane B & C will be the height of the Tank. i.e= H=4 ( ref pic: Water Tank)
Thus height of water in tank is 4/2 ft or 2 ft....................Ans A.
Attachments
Water Tank.jpg [ 108.04 KiB | Viewed 4274 times ]
