Bunuel
A, B, and C were to be paid in proportion to the part of work they did while working on the same piece of work. A and B individually can finish the piece of work in 12 days and 15 days respectively. They worked together for five days and then C completed the remaining work all alone. If $720 was the net sum to be paid for the entire work, what was the average daily wage of B?
(A) $144
(B) $90
(C) $60
(D) $54
(E) $48
Kudos for a correct solution.
Consider work to be 60 units
A can do the work in 12 days i.e. 5 units per day, hence 25 units in 5 days
B can do the same work in 15 days .i.e. 4 units per day, hence 20 units in 5 days
Working together for 5 days A&B complete 45 units in 5 days and remaining 15 units is completed by C.
Now, A did 25 units, B did 20 units and C did 15 units.
Therefore, wage for B is 4/12*720 = $240
Now, 240/5 = $48 per day