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01 Jul 2017, 16:53
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A, B, C, and D are all integers, in that order. The distance between any two adjacent of these numbers is the same. If A= 2^4 and B = 2^8, what is the value of D?
A) 2^5
B) 2^5(8)
C) 2^5(15)
D) 2^5(23)
E) 2^16
Can someone please explain why the answer is D? I cannot seem to fully understand how D was derived from this problem.
Thanks!
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A) 2^5
B) 2^5(8)
C) 2^5(15)
D) 2^5(23)
E) 2^16
Can someone please explain why the answer is D? I cannot seem to fully understand how D was derived from this problem.
Thanks!
Sent from my iPhone using GMAT Club Forum mobile app
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01 Jul 2017, 18:45
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The question says that the distance between any two numbers is same. So B-A= 2^8-2^4=256-16=240. So, C will be 256+240=496 and D will be 496+240= 736. This can also be written as 32*23 and as (2^5)*23
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01 Jul 2017, 19:49
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marinaesmeralda
Hi,
The difference between the two is \(2^8-2^4\)...
D is 3 times that amount away from A.
So \(D = 2^4+3*(2^8-2^4)=2^4*(1+3*(2^4-1))=2^4*(1+3*15)=2^4*(1+45)=2^4*46=2^4*2*23=2^5*23\)
Hence D
Hope it helps!
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
