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A, B, C are positive a^2 + c^2 = 202 What is the value of b - a - c?
1. b^2 + c^2 = 225 2. a^2 + b^2 = 265
Please exaplin your answers.
A for me.
1. a^2+c^2=202 b^2+c^2=225
minus them
b^2-a^2=23----> (b-a)(b+a)=23. b=12 and a=11 then c^2=202-a^2=81 --- > c=9 12-11-9=-8
2. a^2 + c^2 = 202 a^2 + b^2 = 265
minus them
b^2-c^2=63----> (b-c)(b+c)=63, here b=32 c=31 or b=8 c=1 thus not suff.
i could not figure out any other method to solve it.
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Stmt one is Insuff
(b-a)(b+a)= 23 is correct but there are millions of solutions for b and a not just b=12 and a=11. A quick example would be b=sqrt(423) and a=20.
If you have two variables then you need two seperate equations with the same variables to solve. So since we have 3 variables we need 3 seperate equations to solve.
A, B, C are positive a^2 + c^2 = 202 What is the value of b - a - c?
1. b^2 + c^2 = 225 2. a^2 + b^2 = 265
Please exaplin your answers.
Show more
I'm getting C.
stat 1: subtracting a^2 +c^2 = 225 from stat 1 gives us b^2 - a^2 = 23. No good. Insuff.
Stat 2: subtracting a^2 +c^2 = 225 from stat 2 gives us b^2 - c^2 = 63. No good. Insuff.
Together: b^2 + c^2 = 225 (from stat 1) & b^2 - c^2 = 63(see stat 2 above). Adding these two gives us b^2 = 144, which means b = 12 (cannot be -12 due to the stem). Similarly we can solve to get A = 11 and C = 9. Thus, the value of b - a - c can be determined. Suff.
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