a,b,x,and y are positive integers. If a^x*b^y=200, what is

Question

a,b,x,and y are positive integers. If a^x*b^y=200, what is the value of x+y?

S1. a<b
S2. xy=6

techieGuy · Answer

Stmt 1 : Insuff

2 ^1 * 10 ^ 2 = 200 thus x + y = 3

2^ 1 * 100 ^1 = 200 thus x + y = 2

Stmt 2 Insuff 
x* y = 6 ...

2 ^ 3 * 5 ^ 2 thus x + y = 5

1^6 * 200^1 thus x + y = 7

I think should be E

trivikram · Answer

2^3*5^2

So it is B


Since the only value(Atleast I see here ) is 8*25 = 200

v1rok · Answer

What's wrong wit techie's explanation? I think it is a good one. So, it should be (E)

trivikram · Answer

Yeah didnt notice his answer...He is right ..It should be E

freetheking · Answer

OA is E.. Good work!

heman · Answer

a,b,x,and y are positive integers. If a^x*b^y=200, what is the value of x+y?

S1. a x+y =2
 a=5, b= 2, x=2, y =4 --> x+y =6
BCE
(2)
x=2, y=3, a=5,b=2--> x+y =5
x=6, y=1, does not yield Integer values for a,b
Hence B

Heman

a,b,x,and y are positive integers. If a^x*b^y=200, what is

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