GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 20 Nov 2018, 20:00

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in November
PrevNext
SuMoTuWeThFrSa
28293031123
45678910
11121314151617
18192021222324
2526272829301
Open Detailed Calendar
• ### All GMAT Club Tests are Free and open on November 22nd in celebration of Thanksgiving Day!

November 22, 2018

November 22, 2018

10:00 PM PST

11:00 PM PST

Mark your calendars - All GMAT Club Tests are free and open November 22nd to celebrate Thanksgiving Day! Access will be available from 0:01 AM to 11:59 PM, Pacific Time (USA)
• ### Free lesson on number properties

November 23, 2018

November 23, 2018

10:00 PM PST

11:00 PM PST

Practice the one most important Quant section - Integer properties, and rapidly improve your skills.

# A bag contains 6 red balls, 11 yellow balls and 5 pink balls. If two b

Author Message
TAGS:

### Hide Tags

Manager
Joined: 06 Oct 2015
Posts: 91
A bag contains 6 red balls, 11 yellow balls and 5 pink balls. If two b  [#permalink]

### Show Tags

Updated on: 24 Oct 2018, 07:59
00:00

Difficulty:

25% (medium)

Question Stats:

69% (01:22) correct 31% (01:18) wrong based on 49 sessions

### HideShow timer Statistics

A bag contains 6 red balls, 11 yellow balls and 5 pink balls. If two balls are drawn at random from the bag, one after another, what is the probability that first ball is red and the second ball is yellow?

(A) 1/14

(B) 1/7

(C) 2/7

(D) 5/7

(E) 3/14

Originally posted by NaeemHasan on 24 Oct 2018, 04:02.
Last edited by chetan2u on 24 Oct 2018, 07:59, edited 1 time in total.
Corrected the OA
Manager
Joined: 09 Jun 2014
Posts: 193
Location: India
Concentration: General Management, Operations
Schools: Tuck '19
Re: A bag contains 6 red balls, 11 yellow balls and 5 pink balls. If two b  [#permalink]

### Show Tags

24 Oct 2018, 07:20
NaeemHasan wrote:
A bag contains 6 red balls, 11 yellow balls and 5 pink balls. If two balls are drawn at random from the bag, one after another, what is the probability that first ball is red and the second ball is yellow?

(A) 1/14

(B) 1/7

(C) 2/7

(D) 5/7

(E) 3/14

So,I would approach this problem as below

R=6
Y=11
B=5

So 6C1/22C1 * 11C1/ 21C1

Note red= since we havewithdrawn one ball so net will be 22-1= 21 balls and now we have to pick yellow out of the total these 21 balls

(6*11 ) / (22*21) = 1/7

So OA should be 1/7

Press Kudos if it helps!!
Board of Directors
Status: QA & VA Forum Moderator
Joined: 11 Jun 2011
Posts: 4230
Location: India
GPA: 3.5
Re: A bag contains 6 red balls, 11 yellow balls and 5 pink balls. If two b  [#permalink]

### Show Tags

24 Oct 2018, 07:42
NaeemHasan wrote:
A bag contains 6 red balls, 11 yellow balls and 5 pink balls. If two balls are drawn at random from the bag, one after another, what is the probability that first ball is red and the second ball is yellow?

(A) 1/14

(B) 1/7

(C) 2/7

(D) 5/7

(E) 3/14

We have 6R , 11Y & 5P

We have to pick 1st Red Ball so probability of that is $$\frac{6}{22}$$
Next we pick 1 Yellow ball , so the probability is $$\frac{11}{21}$$

Total probability is $$\frac{6}{22}$$*$$\frac{11}{21} = \frac{1}{7}$$; Answer must be (B)
_________________

Thanks and Regards

Abhishek....

PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS

How to use Search Function in GMAT Club | Rules for Posting in QA forum | Writing Mathematical Formulas |Rules for Posting in VA forum | Request Expert's Reply ( VA Forum Only )

Manager
Joined: 06 Oct 2015
Posts: 91
Re: A bag contains 6 red balls, 11 yellow balls and 5 pink balls. If two b  [#permalink]

### Show Tags

24 Oct 2018, 09:08
The OA is given 2/7. Total number of ways to select 2 balls is 22C2. The number of ways to select red ball is 6C1 and the number of ways to select yellow ball is 11C1.
Hence, probability = 6C1*11C1/22C2= 2/7
Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 4170
Location: United States (CA)
Re: A bag contains 6 red balls, 11 yellow balls and 5 pink balls. If two b  [#permalink]

### Show Tags

25 Oct 2018, 16:52
NaeemHasan wrote:
A bag contains 6 red balls, 11 yellow balls and 5 pink balls. If two balls are drawn at random from the bag, one after another, what is the probability that first ball is red and the second ball is yellow?

(A) 1/14

(B) 1/7

(C) 2/7

(D) 5/7

(E) 3/14

We are not replacing the first ball after it is drawn. Thus, the probability is:

6/22 x 11/21 = 3/11 x 11/21 = 3/21 = 1/7.

_________________

Scott Woodbury-Stewart
Founder and CEO

GMAT Quant Self-Study Course
500+ lessons 3000+ practice problems 800+ HD solutions

Re: A bag contains 6 red balls, 11 yellow balls and 5 pink balls. If two b &nbs [#permalink] 25 Oct 2018, 16:52
Display posts from previous: Sort by