Bunuel wrote:

A bag of snack mix contains 3 ounces of pretzels, 1 ounce of chocolate chips, 2 ounces of mixed nuts, and x ounces of dried fruit by weight. What percent of the mix is dried fruit, by weight?

(A) \(\frac{x}{600}\)

(B) \(\frac{100}{6x}\)

(C) \(\frac{100x}{6}\)

(D) \(\frac{100x}{x+6}\)

(E) \(\frac{x}{100(x+6)}\)

In the mixture, each item's weight in ounces

P = 3

C = 1

N = 2

F = x

Dried fruit is what percent of the mix, by weight?

Total ounces: \((P+C+N+F)=(3+1+2+x)=\)

\((x+6)\)

Dried fruit, # of ounces: \(F=x\)

Dried fruit as a percent of mix: \((\frac{Part}{Whole}*100)=(\frac{FruitOz}{TotalOz}*100)\)

\((\frac{x}{x+6}*\frac{100}{1})=\frac{100x}{x+6}\)

Answer D

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