Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Learn the winning strategy for a high GRE score — what do people who reach a high score do differently? We're going to share insights, tips and strategies from data we've collected from over 50,000 students who used examPAL.

Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT.

A bar is creating a new signature drink. There are five possible alcoh
[#permalink]

Show Tags

14 Apr 2017, 02:40

3

00:00

A

B

C

D

E

Difficulty:

5% (low)

Question Stats:

90% (00:43) correct 10% (00:44) wrong based on 188 sessions

HideShow timer Statistics

A bar is creating a new signature drink. There are five possible alcoholic ingredients in the drink: rum, vodka, gin, peach schnapps, or whiskey. There are five possible non-alcoholic ingredients: cranberry juice, orange juice, pineapple juice, lime juice, or lemon juice. If the bar uses two alcoholic ingredients and two non-alcoholic ingredients, how many different drinks are possible?

Re: A bar is creating a new signature drink. There are five possible alcoh
[#permalink]

Show Tags

14 Apr 2017, 05:44

3

Top Contributor

Bunuel wrote:

A bar is creating a new signature drink. There are five possible alcoholic ingredients in the drink: rum, vodka, gin, peach schnapps, or whiskey. There are five possible non-alcoholic ingredients: cranberry juice, orange juice, pineapple juice, lime juice, or lemon juice. If the bar uses two alcoholic ingredients and two non-alcoholic ingredients, how many different drinks are possible?

A. 25 B. 50 C. 75 D. 100 E. 3600

Take the task of making a drink and break it into stages.

Stage 1: Select two alcoholic ingredients for the drink Since the order in which we select the ingredients does not matter, we can use combinations. We can select 2 ingredients from 5 ingredients in 5C2 ways (10 ways) So, we can complete stage 1 in 10 ways

If anyone is interested, we have a video on calculating combinations (like 5C2) in your head (see below)

Stage 2: Select two non-alcoholic ingredients for the drink We'll use combinations again. We can select 2 ingredients from 5 ingredients in 5C2 ways (10 ways) So, we can complete stage 2 in 10 ways

By the Fundamental Counting Principle (FCP), we can complete the 2 stages (and thus create a drink) in (10)(10) ways (100 ways)

A bar is creating a new signature drink. There are five possible alcoh
[#permalink]

Show Tags

17 Apr 2017, 23:44

chinelj wrote:

Can you explain why the solution isnt 5!/2!3! ?

A bar is creating a new signature drink. There are five possible alcoholic ingredients in the drink: rum, vodka, gin, peach schnapps, or whiskey. There are five possible non-alcoholic ingredients: cranberry juice, orange juice, pineapple juice, lime juice, or lemon juice. If the bar uses two alcoholic ingredients and two non-alcoholic ingredients, how many different drinks are possible?

The question ask for the combination of 2 alcoholic ingredient selection and 2 non-alcoholic ingredient selection. There is a "and" in-between !! and means multiply.

Now calculate the selection of 2 alcoholic ingredient first. It is given by - 5!/2!*3!. Similarly, calculate the selection of 2 alcoholic ingredient. It is given by - 5!/2!*3!.

now we need to multiply both to get the final answer, which is given by = selection of 2 alcoholic ingredient* selection of 2 non-alcoholic ingredient i.e. (5!/2!*3!)*(5!/2!*3!).

A bar is creating a new signature drink. There are five possible alcoh
[#permalink]

Show Tags

24 Jul 2017, 17:54

Bunuel wrote:

A bar is creating a new signature drink. There are five possible alcoholic ingredients in the drink: rum, vodka, gin, peach schnapps, or whiskey. There are five possible non-alcoholic ingredients: cranberry juice, orange juice, pineapple juice, lime juice, or lemon juice. If the bar uses two alcoholic ingredients and two non-alcoholic ingredients, how many different drinks are possible?

A. 25 B. 50 C. 75 D. 100 E. 3600

1. There are four slot : 2 for alcoholic and 2 for non alcoholic.

2. For alcoholic, we can count for 2 slots : \(\frac{(5 X 4)}{(2 X 1)}\) = 10 We use 2 X 1 in denominator because we should eliminate the 2 double counting (Rum and Vodka combination is same with Vodka and Rum combination)

3. For non alcoholic, we can count in the exactly same way with non alcoholic. Total possibilites : 10.

4. Combine (2) and (3), we get 10 X 10 = 100. Therefore D.

Re: A bar is creating a new signature drink. There are five possible alcoh
[#permalink]

Show Tags

26 Jul 2017, 15:36

1

Bunuel wrote:

A bar is creating a new signature drink. There are five possible alcoholic ingredients in the drink: rum, vodka, gin, peach schnapps, or whiskey. There are five possible non-alcoholic ingredients: cranberry juice, orange juice, pineapple juice, lime juice, or lemon juice. If the bar uses two alcoholic ingredients and two non-alcoholic ingredients, how many different drinks are possible?

A. 25 B. 50 C. 75 D. 100 E. 3600

The number of ways we can choose two alcoholic ingredients from five is 5C2 = 5!/[2!(5-2)!] = (5 x 4)/2! = 10, and the number of ways we can choose two non-alcoholic ingredients from five is the same: 5C2 = 10. Thus, the total number of ways we can choose two alcoholic ingredients and two non-alcoholic ingredients is 10 x 10 = 100.

Answer: D
_________________

Scott Woodbury-Stewart Founder and CEO

GMAT Quant Self-Study Course 500+ lessons 3000+ practice problems 800+ HD solutions

Re: A bar is creating a new signature drink. There are five possible alcoh
[#permalink]

Show Tags

18 Dec 2018, 22:33

No of possible combinations = 5C2 (ways of choosing 2 alcoholic drinks from 5 alcoholic drinks) x 5C2(ways of choosing 2 non-alcoholic drinks from 5 no-alcoholic drinks)= 10 x 10 = 100.

gmatclubot

Re: A bar is creating a new signature drink. There are five possible alcoh &nbs
[#permalink]
18 Dec 2018, 22:33