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Bunuel
A basketball coach has won 65 percent of the 400 games she has coached in her career. If she will coach 100 more games before retirement, how many must she win to raise her winning percentage to 70 percent?

A. 50
B. 65
C. 75
D. 90
E. 100

We are given that a coach won 0.65 x 400 = 260 games in her career. She is coaching 100 more games and we need to determine how many she must win to have a winning percentage of 70 percent. We can let w = the number of remaining games she must win.

(260 + w)/(400 + 100) = 70/100

(260 + w)/500 = 7/10

10(260 + w) = 3500

260 + w = 350

w = 90

Answer: D
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Current games won = (65/100) * 400 = 260
Games won at 70% win rate in 100 additional games = (70/100) * 500 = 350
Additional games coach needs to win = 350 - 260 = 90. Answer D
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Games won this far => 65/100 * 400 => 260

Total matches she need to win => 70/100 * 500 => 350


So she must win => 350-260=> 90 games more.

Smash that D.
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Bunuel
A basketball coach has won 65 percent of the 400 games she has coached in her career. If she will coach 100 more games before retirement, how many must she win to raise her winning percentage to 70 percent?

A. 50
B. 65
C. 75
D. 90
E. 100

260+x/5 = .7
x= 90
IMO D
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