Bunuel

A boat leaves point A heading directly across the river to point P, 120 yards away. A swift current immediately changes the boat’s direction, causing it to land instead at point B. How many yards is point B from the intended destination, P?
A. 40
B. 45
C. 60
D. \(40 \sqrt{3}\)
E. \(60 \sqrt{3}\)
Attachment:
2016-02-07_2125.png
∆ APB is a 30-60-90 special triangle
Vertex P = 90°, vertex A = 30°
Vertex B must = 60° (180° in a triangle)
We have a 30-60-90 triangle
Sides opposite those angles, respectively, are in ratio \(x: x\sqrt{3}: 2x\)
Length of BP, opposite the 30° angle = \(x\)
Side AP = 120 and is opposite the 60° angle
Length of 120 thus corresponds with \(x\sqrt{3}\)
Set them equal, solve for
\(x\)
\(120=x\sqrt{3}\)
\(x=\frac{120}{\sqrt{3}}\)
\(x=(\frac{120}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}})=\frac{120\sqrt{3}}{3}=40\sqrt{3}\)Point B is \(40\sqrt{3}\) yards from P
Answer D