A bookseller has two display windows. She plans to display 4 new fict

Answer is combination of left window:

4! = 4 * 3 * 2

AND (means multiply)

3! = 3*2

together 4 * 3 * 2 * 3 * 2 = 144

Answer C

Left hand side books can be ordered in 4! ways = 24 ways
Right hand side books can be ordered in 3! ways = 6 ways

Total number of ways = 24 * 6
= 144
Hence option C.

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MAGOOSH OFFICIAL SOLUTION:

The left window will have permutations of the 4 fiction books, so the number of possibilities for that window is
permutations = 4! = (4)(3)(2)(1) = 24

The right window will have permutations of the 3 non-fiction books, so the number of possibilities for that window is
permutations = 3! = (3)(2)(1) = 6

Any of the 24 displays of the left window could be combined with any of the 6 displays of the right window, so the total number of configurations is 24*6 = 144

Answer: C.

Hi All,

We're told that a bookseller has two display windows - and she plans to display 4 new fiction books in the left window and 3 new non-fiction books in the right window. Assuming she can put the four fiction books in any order, and separately, the three non-fiction books in any order, how many total configurations will there be for the two display windows. This is a mid-level Permutation question and requires just a bit of multiplication to solve.

To start, since we are putting the books in order (without any restrictions), we can use basic multiplication (re: factorials) to solve:

For the 4 fiction books, there are 4! = (4)(3)(2)(1) = 24 ways to arrange those books in the window
For the 3 non-fiction books, there are 3! = (3)(2)(1) = 6 ways to arrange those books in the window
In total, we have (24)(6) = 144 different ways to arrange the books.

Final Answer:

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The number of configurations is 4! x 3! = 24 x 6 = 144.

Answer: C