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24 Jan 2024, 03:57
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A
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Difficulty:
25%
(medium)
Question Stats:
81% (01:39) correct
19%
(01:56)
wrong
based on 296
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A bookstore customer bought 3 books at different prices, and the highest price was $8 more than the median price. Was the average (arithmetic mean) price of the 3 books greater than the median price?
(1) The lowest price of the 3 books was $2 less than the median price.
(2) The median price of the 3 books was $30.
2024-01-24_14-57-00.png [ 49.22 KiB | Viewed 3910 times ]
(1) The lowest price of the 3 books was $2 less than the median price.
(2) The median price of the 3 books was $30.
Attachment:
2024-01-24_14-57-00.png [ 49.22 KiB | Viewed 3910 times ]
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26 Jan 2024, 22:57
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guddo
(1) The lowest price of the \(3\) books was \($2\) less than the median price.
So we have \(m-2, m , m+8 \) where m is the median.
Is \(\frac{3m+6}{3} > m\) or is \(3m+6>3m\) or is \(6>0 \), we can answer a definite YES.
SUFF.
(2) The median price of the \(3\) books was \($30.\)
We have no info on the other two prices.
INSUFF.
Ans A
Hope it helped.
28 Jan 2024, 08:27
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guddo
Statement 1
(1) The lowest price of the 3 books was $2 less than the median price.
Attachment:
Screenshot 2024-01-28 205129.png [ 20.13 KiB | Viewed 4145 times ]
Median Price = m
Average Price = \(\frac{m - 2 + m + m + 8 }{3} = \frac{3m + 6}{3} = m + 2\)
Was the average (arithmetic mean) price of the 3 books greater than the median price? → Yes
This statement alone is sufficient to answer the question asked. Eliminate B, C, and E.
Statement 2
(2) The median price of the 3 books was $30.
We don't have any information on the cost price of the third book. Hence, we cannot conclude on the average price of the three books. This statement alone is not sufficient to answer the question.
Option A
