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# A bowl contains equal numbers of red, orange, green, blue, a

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Manager
Joined: 26 Jul 2011
Posts: 108
Location: India
WE: Marketing (Manufacturing)
A bowl contains equal numbers of red, orange, green, blue, a [#permalink]

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02 May 2013, 12:38
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Difficulty:

35% (medium)

Question Stats:

75% (01:33) correct 25% (01:36) wrong based on 350 sessions

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A bowl contains equal numbers of red, orange, green, blue, and yellow candies. Kaz eats all of the green candies and half of the orange ones. Next, he eats half of the remaining pieces of each color. Finally, he eats red and yellow candies in equal proportions until the total number of remaining candies of all colors equals 15% of the original number. What percent of the red candies remain?

A. 0%
B. 5%
C. 10%
D.15%
E. 20%
[Reveal] Spoiler: OA
VP
Status: Far, far away!
Joined: 02 Sep 2012
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Location: Italy
Concentration: Finance, Entrepreneurship
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Re: A bowl contains equal numbers of red, orange, green, blue, [#permalink]

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02 May 2013, 12:47
R | O | G | B | Y - colors
10 | 10 | 10 | 10 | 10 - initial situation
10 | 5 | X | 10 | 10 - eats all G and half O
5 | 2.5 | X | 5 | 5 - eats half of the remaining

Now we know that remain 15% of 50 => $$50*15%=7.5$$ candies. We have to "eat" R and Y till the remaining candies will be 7.5.

We have to eat ALL R and Y.

0 | 2.5 | X | 5 | 0 = 7.5 remains

$$%$$of $$R$$ = $$0%$$
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Manager
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Posts: 74
Re: A bowl contains equal numbers of red, orange, green, blue, [#permalink]

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02 May 2013, 16:14
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See image attached.
Remianing RED candies = 0
hence 0%

Ans A
Attachments

Candies.JPG [ 40.04 KiB | Viewed 5990 times ]

Intern
Joined: 14 Mar 2013
Posts: 48
Location: United States
Concentration: General Management, Leadership
GMAT Date: 12-03-2013
WE: General Management (Retail)
Re: A bowl contains equal numbers of red, orange, green, blue, a [#permalink]

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19 Nov 2013, 15:49
Did almost the same as Zarrolou did. I just used numbers that sum 100, I think this is easier to work with % using numbers that sum 100.

R | O | G | B | Y - colors
20 | 20 | 20 | 20 | 20 - initial situation
20 | 10 | 0 | 20 | 20 - eats all G and half O
10 | 5 | 0 | 10 | 10 - eats half of the remaining
0 | 5 | X | 10 | 0 - eats R and Y candies in equal proportions until the total number of remaining candies of all colors equals 15%

Ans A
Manager
Joined: 21 Oct 2013
Posts: 191
Location: Germany
GMAT 1: 660 Q45 V36
GPA: 3.51
Re: A bowl contains equal numbers of red, orange, green, blue, a [#permalink]

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23 Jun 2014, 04:04
Pick smart numbers here. 5 different colors of candy: Let's 100 Total, hence 20 pieces each in original. In the end we want to have 15 % of original total, so 15 candies.

20 R + 20 O + 20 G + 20 B + 20 Y = TOTAL (original=100)
First step: Eats all green and half of orange:
20 R + 10 O + 0 G + 20 B + 20 Y = Total (new=70)
Second step: Eats half of the remaining:
10 R + 5 O + 0 G + 10 B + 10 Y = Total (new = 35)
third step: eats equal of R and Y so that 15 % of the ORIGINAL TOTAL remain (=15 candies)
Hence he eats all red and all yellow candies:
5 O + 10 B = 15 Total

Hence we get Answer A: 0 % of red candies remain!
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Re: A bowl contains equal numbers of red, orange, green, blue, a [#permalink]

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21 Mar 2018, 13:37
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Re: A bowl contains equal numbers of red, orange, green, blue, a   [#permalink] 21 Mar 2018, 13:37
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# A bowl contains equal numbers of red, orange, green, blue, a

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