|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
18 Dec 2024, 08:40
Kudos
Bookmarks
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
100% (01:25) correct
0% (00:00) wrong based on 5 sessions
History
Date
Time
Result
Not Attempted Yet
A bullet train leaves Kyoto for Tokyo traveling 240 miles per hour at 12 noon. Ten minutes later, a train leaves Tokyo for Kyoto traveling 160 miles per hour. If Tokyo and Kyoto are 300 miles apart, at what time will the trains pass each other?
(A) 12:40pm
(B) 12:49pm
(C) 12:55pm
(D) 1:00pm
(E) 1:05pm
(A) 12:40pm
(B) 12:49pm
(C) 12:55pm
(D) 1:00pm
(E) 1:05pm
25 Dec 2024, 09:56
Kudos
Bookmarks
OE
Solve this problem by filling in the RTD chart. Note that the train going from Kyoto to Tokyo leaves first, so its time is longer by 10 minutes, which is 1/6 hour.
Next, write the expressions for the distance that each train travels, in terms of t. Now, sum those distances and set that total equal to 300 miles:
\(240(t+\frac{1}{6})+160t = 300\)
\(240t+40+160t= 300\)
\(\\
400t=260\\
20t=13\\
\)
\(t=\frac{13}{20} \)hours \(= \frac{39}{60}\) hours = 39 minutes
The first train leaves at 12 noon. The second train leaves at 12:10pm. Thirty-nine minutes aȇer the second train has left, at 12:49pm, the trains pass each other.
1.jpg [ 57.35 KiB | Viewed 402 times ]
Solve this problem by filling in the RTD chart. Note that the train going from Kyoto to Tokyo leaves first, so its time is longer by 10 minutes, which is 1/6 hour.
Next, write the expressions for the distance that each train travels, in terms of t. Now, sum those distances and set that total equal to 300 miles:
\(240(t+\frac{1}{6})+160t = 300\)
\(240t+40+160t= 300\)
\(\\
400t=260\\
20t=13\\
\)
\(t=\frac{13}{20} \)hours \(= \frac{39}{60}\) hours = 39 minutes
The first train leaves at 12 noon. The second train leaves at 12:10pm. Thirty-nine minutes aȇer the second train has left, at 12:49pm, the trains pass each other.
Attachment:
1.jpg [ 57.35 KiB | Viewed 402 times ]
