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09 Feb 2021, 04:00
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
68% (02:12) correct
32%
(02:55)
wrong
based on 268
sessions
History
Date
Time
Result
Not Attempted Yet
A can do a piece of work in 16 days which B can doin 24 days. They begin together but 4 days before the completion of the work, A leaves off. The total number of days to complete the work is
(A) 6 3/5
(B) 8
(C) 8 ½
(D) 12
(E) 13 ½
(A) 6 3/5
(B) 8
(C) 8 ½
(D) 12
(E) 13 ½
11 Feb 2021, 07:17
Kudos
Bookmarks
Work done by A & B in 1 day = 1/16 + 1/24 = 5/48
Work done by B alone in 4 days = 4 * 1/24 = 1/6
Remaining work done by A & B together = 1-1/6 = 5/6
Time taken to do 5/6 of work by A&B together = 48/5 * 5/6 = 8 days
Total time 8 days + 4 days when B alone completed the work = 12 days
Do you guys think it is a gmat type question ?
Work done by B alone in 4 days = 4 * 1/24 = 1/6
Remaining work done by A & B together = 1-1/6 = 5/6
Time taken to do 5/6 of work by A&B together = 48/5 * 5/6 = 8 days
Total time 8 days + 4 days when B alone completed the work = 12 days
Do you guys think it is a gmat type question ?
11 Feb 2021, 08:51
Kudos
Bookmarks
W=RT
A's 1 day work = \(\frac{1}{16}\)
B's 1 day work =\(\frac{ 1}{24}\)
A left 4 days before the work was completed
B's 4 day work =\( \frac{1}{24}\) * 4 = 1/6
Remaining work = \(\frac{5}{6}\) done by both A & B
\(\frac{5}{6}\) = \([\frac{1}{16}+\frac{1}{24}]T\)
On solving:
T = 8 days
Total time = 8+4 = 12 days (D)
A's 1 day work = \(\frac{1}{16}\)
B's 1 day work =\(\frac{ 1}{24}\)
A left 4 days before the work was completed
B's 4 day work =\( \frac{1}{24}\) * 4 = 1/6
Remaining work = \(\frac{5}{6}\) done by both A & B
\(\frac{5}{6}\) = \([\frac{1}{16}+\frac{1}{24}]T\)
On solving:
T = 8 days
Total time = 8+4 = 12 days (D)
