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03 Mar 2021, 06:30
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
37% (02:09) correct
63%
(02:19)
wrong
based on 76
sessions
History
Date
Time
Result
Not Attempted Yet
A car can hold 3 people in the front seat and 4 in the back seat. In how many ways can 7 people be seated in the car if 2 particular people must sit in the back seat and 1 particular person is the driver?
A. 36
B. 48
C. 72
D. 144
E. 288
A. 36
B. 48
C. 72
D. 144
E. 288
03 Mar 2021, 06:36
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The driver can be seated in 1 way.
The 2 people who have to sit in the back seat can sit in 2 ways (AB or BA)
The remaining 4 people can be seated in 4 seats in 4! = 24 ways
Total number of ways = 1 * 2 * 24 = 48
Option B
Arun Kumar
The 2 people who have to sit in the back seat can sit in 2 ways (AB or BA)
The remaining 4 people can be seated in 4 seats in 4! = 24 ways
Total number of ways = 1 * 2 * 24 = 48
Option B
Arun Kumar
12 Mar 2021, 09:43
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Bunuel
Let the seven people be \(a, b, c, d, e , f\) and \(g\)
let \(a \)and \(b\) be fixed for back seat and let \(d\) be the driver
Back seat:
Let us choose \(2\) seats from the \(4\) seats for \(a\) and \(b\), this can be done in =\( 4C2 \)
\(a\) and \(b\) can be arranged among themselves in \(2!\) ways
for the remaining two seats we have \(4*3\) choices
Front seat:
The driver can only be seated in 1 way
For the remaining two seats we have two people hence they can be seated in \(2*1\) ways
Total ways = \(4C2*2!*4*3*2 = 288\)
Ans-E
Hope it's clear
