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Bunuel
A certain auto manufacturer sold 3% fewer vehicles in 2007 than in 2006. If the manufacturer sold 2.1 million vehicles in 2006, how many vehicles, to the nearest 10,000, did the manufacturer sell in 2007?

A. 63,000
B. 2,000,000
C. 2,030,000
D. 2,040,000
E. 2,300,000

\(2100000 * \frac{97}{100}\)

= \(2037000\)

~ \(2,040,000\) , Answer must be (D)
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Bunuel
A certain auto manufacturer sold 3% fewer vehicles in 2007 than in 2006. If the manufacturer sold 2.1 million vehicles in 2006, how many vehicles, to the nearest 10,000, did the manufacturer sell in 2007?

A. 63,000
B. 2,000,000
C. 2,030,000
D. 2,040,000
E. 2,300,000

The number of vehicles sold in 2007 is 2.1 x 0.97 = 2.037 million ≈ 2,040,000.

Answer: D
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