LakerFan24 wrote:
A certain car company manufactured x cars at a cost of c dollars per car. If a certain number of cars were sold below cost at a sale price of s dollars per car, while the rest of the cars were sold for the normal retail price of n dollars per car, how many cars could the company afford to sell at the sale price in order to break even (no profit and no loss)?
(A) \(\frac{x(c-n)}{(s-n)}\)
(B) \(\frac{x(n-c)}{(s-n)}\)
(C) \(\frac{x(c-n)}{(s-c)}\)
(D) \(\frac{x(s-n)}{(c-n)}\)
(E) (x-n)(x-s)
P.S. we definitely need more of these question types on this forum. they definitely pop up on the practice CATs i've taken from all the different major test prep companies
This is indeed a very realistic GMAT question- other examples include (see
Kaplan) express x y z etc- basically the ability to express three variables. Anyways, what this question is simply stating is that with a specific amount of cars produced, how many cars could be sold at a lower cost than the cost it took to produce them- so if took $30,000.00 to make each Tesla car out of a batch of 100 then how many Tesla's could be sold out of that batch of 100 for a price less than $30,000- assuming, remember, that the only other price offered by Tesla will be sold at a price higher
higher than $30,000. That is to say if the total cost of producing all these Tesla cars is $3,000,000 then what amount of Tesla's sold at a price below $30,000 would add up to $3,000,000 if the other Tesla cars must be sold at a constant price above the production cost. Basically $30,000 (S) + $30,0000(N)= X (C)- but we can use even simpler numbers
x= 100
c= 2.00
s= 1.00
n=3.00
Only A satisfies the condition
Thus
"A"