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A certain computer file contains 8,000 data records, each of which nee

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pushpitkc
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A certain computer file contains 8,000 data records, each of which nee [#permalink] New post   Updated on: 02 Nov 2018, 04:18
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A certain computer file contains 8,000 data records, each of which needs to be updated. If it takes 20 seconds to update 100 records, then at the same rate, approximately how many minutes will it take to update all of the records in the file?

(A) 16
(B) 27
(C) 67
(D) 80
(E) 160
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B

Originally posted by pushpitkc on 02 Nov 2018, 04:14.
Last edited by Bunuel on 02 Nov 2018, 04:18, edited 1 time in total.
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Re: A certain computer file contains 8,000 data records, each of which nee [#permalink] New post   02 Nov 2018, 04:23
It basicall takes 1 second to update 5 data records , thus according to this rate it will take approx 27 seconds to update 8000 data records

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Re: A certain computer file contains 8,000 data records, each of which nee [#permalink] New post   11 Nov 2018, 23:32
pushpitkc wrote:
A certain computer file contains 8,000 data records, each of which needs to be updated. If it takes 20 seconds to update 100 records, then at the same rate, approximately how many minutes will it take to update all of the records in the file?

(A) 16
(B) 27
(C) 67
(D) 80
(E) 160


Total Work = 8000 pages updation

Rate = 100 pages per 20 seconds

Or 300 pages per minute

Time required to update 8000 pages = Work / Rate

Time = 8000/300 = 26.66 = 27

Hence (B)
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BrentGMATPrepNow
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Re: A certain computer file contains 8,000 data records, each of which nee [#permalink] New post   02 Dec 2020, 10:14
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pushpitkc wrote:
A certain computer file contains 8,000 data records, each of which needs to be updated. If it takes 20 seconds to update 100 records, then at the same rate, approximately how many minutes will it take to update all of the records in the file?

(A) 16
(B) 27
(C) 67
(D) 80
(E) 160


We can solve this question using equivalent ratios:

Let x = the number of SECONDS to update all 8000 records.

We can write: 20/100 = x/8000
Cross multiply: 100x = (20)(8000)
Simplify: 100x = 160,000
Solve: x = 1600 SECONDS

To convert 1600 seconds to MINUTES, divide 1600 by 60 to get: 1600/60 = 160/6 = 80/3 = a little more then 25 (since 75/3 = 25, I know that 80/3 is a little more than 25)

Answer:B

Cheers,
Brent
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Re: A certain computer file contains 8,000 data records, each of which nee [#permalink] New post   27 Oct 2022, 18:35
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pushpitkc wrote:
A certain computer file contains 8,000 data records, each of which needs to be updated. If it takes 20 seconds to update 100 records, then at the same rate, approximately how many minutes will it take to update all of the records in the file?

(A) 16
(B) 27
(C) 67
(D) 80
(E) 160


Since it takes 20 seconds to update 100 records, it takes 1/3 of a minute to update 100 records. Thus, the rate is work/time = 100/(1/3) = 300.

Now, we can determine how long it takes to update 8,000 data records.

Time = work/rate

Time = 8,000/300 = 80/3 = 26 2/3 or about 27 minutes.

Answer: B
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Re: A certain computer file contains 8,000 data records, each of which nee [#permalink]
27 Oct 2022, 18:35
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