Bunuel
A certain organization sells boxes of 32 oranges for $8.00 per box, boxes of 20 grapefruit for $7.00 per box, and combination boxes of oranges and grapefruit for $8.50 per box. If the unit price of each kind of fruit is independent of the kind of box in which it is packed and if each combination box contains twice as many oranges as grapefruit, how many grapefruit must be in a combination box?
A. 6
B. 7
C. 8
D. 10
E. 17
PS20477
A certain organization sells boxes of 32 oranges for $8.00 per box, boxes of 20 grapefruit for $7.00 per boxPrice PER ORANGE = $8.00/32 = $1/4 =
$0.25Price PER GRAPEFRUIT = $7.00/20 =
$0.35Each combination box contains TWICE as many oranges as grapefruitLet
G = the NUMBER of grapefruit in the box
So,
2G = the NUMBER of oranges in the box
Combination boxes of oranges and grapefruit for $8.50 per boxWe can write: (
G)(
0.35) + (
2G)(
$0.25) = 8.50
Simplify: 0.35G + 0.5G = 8.50
Simplify: 0.85G = 8.50
Solve: G = 8.50/0.85 =
10So, there are
10 grapefruit in the combination box
Answer: D
Cheers,
Brent