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# A certain store sells only records and CDs. All CDs cost \$7.82, includ

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Re: A certain store sells only records and CDs. All CDs cost \$7.82, includ [#permalink]
pushpitkc wrote:
1
7.82x + 4.18y < 25(y - total number of records bought , x - total number of CDs bought) If x=0 & y >= 6, the total cost cannot be less than 25.
When the number of CDs is greater than 0, this statement is obviously going to fail.
Hence, this condition is sufficient.

2 He bought atleast one CD. However we don't know the total amount he spent at the store. So he could have bought any 2 number of CDs or even 6 number of CDs.

This condition alone is not sufficient. (Option A) is the solution

hello
Can you please explain how & y >= 6?
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Re: A certain store sells only records and CDs. All CDs cost \$7.82, includ [#permalink]
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eantolovic wrote:
Hello Brent,

I appreciate your logic in answering this question; however, I am struggling on a fundamental necessity in order to make this true. Statement (1) declares "Yesterday, John spent less than \$25 at the store." It doesn't say what he spent that money on, whether it was CD's, records, or candy at the register. Therefore, we cannot determine whether he bought 6 records, 5 records and some candy, or none at all. On behalf of this logic I can only surmise that Statement (1) is insufficient evidence in order to answer "Yesterday, did John buy more than 5 records at this store?"

Statement (2) would also be insufficient since we are still unaware whether John bought more than 5 records.

Since Statements (1) & (2) are insufficient, we can now determine if they can be combined. If (1) states John spent less than \$25, and (2) states John bought at least 1 CD, then we now know for sure that John wouldn't have enough remaining funds to buy those 5 rad vinyls on display. Therefore, and according to this line of reasoning, the answer would be .

Be careful. The part in blue above is not correct.
While we may not know exactly what was purchased, we can be certain that John did NOT buy 6 records (because that would cost more than \$25)
We can also be certain that John did NOT buy 7 records (because that would cost more than \$25)
We can also be certain that John did NOT buy 8 records (because that would cost more than \$25)
We can also be certain that John did NOT buy 9 records (because that would cost more than \$25)
We can also be certain that John did NOT buy 10 records (because that would cost more than \$25)
.....etc

So, even though we have no idea what John purchased, we can be 100% that John did NOT buy 6, 7, 8, 9, 10, (etc) records.
In other words, we can definitively answer the target question with a resounding "NO"

Does that help?

Cheers,
Brent
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Re: A certain store sells only records and CDs. All CDs cost \$7.82, includ [#permalink]
GMATPrepNow wrote:
eantolovic wrote:
Hello Brent,

I appreciate your logic in answering this question; however, I am struggling on a fundamental necessity in order to make this true. Statement (1) declares "Yesterday, John spent less than \$25 at the store." It doesn't say what he spent that money on, whether it was CD's, records, or candy at the register. Therefore, we cannot determine whether he bought 6 records, 5 records and some candy, or none at all. On behalf of this logic I can only surmise that Statement (1) is insufficient evidence in order to answer "Yesterday, did John buy more than 5 records at this store?"

Statement (2) would also be insufficient since we are still unaware whether John bought more than 5 records.

Since Statements (1) & (2) are insufficient, we can now determine if they can be combined. If (1) states John spent less than \$25, and (2) states John bought at least 1 CD, then we now know for sure that John wouldn't have enough remaining funds to buy those 5 rad vinyls on display. Therefore, and according to this line of reasoning, the answer would be .

Be careful. The part in blue above is not correct.
While we may not know exactly what was purchased, we can be certain that John did NOT buy 6 records (because that would cost more than \$25)
We can also be certain that John did NOT buy 7 records (because that would cost more than \$25)
We can also be certain that John did NOT buy 8 records (because that would cost more than \$25)
We can also be certain that John did NOT buy 9 records (because that would cost more than \$25)
We can also be certain that John did NOT buy 10 records (because that would cost more than \$25)
.....etc

So, even though we have no idea what John purchased, we can be 100% that John did NOT buy 6, 7, 8, 9, 10, (etc) records.
In other words, we can definitively answer the target question with a resounding "NO"

Does that help?

Cheers,
Brent

Yes, it does. I do realize that studying all day can lead to hopeless errors, but my mind must have been so tangled yesterday to overlook something so simple as that Thank you for the reply and I apologize for the unnecessary challenge. I'll delete my comment in order not to confuse any others. Have a great day!
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Re: A certain store sells only records and CDs. All CDs cost \$7.82, includ [#permalink]
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Re: A certain store sells only records and CDs. All CDs cost \$7.82, includ [#permalink]
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