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A certain vegetable stand sold potatoes for $1.40 each and
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Kritesh
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A certain vegetable stand sold potatoes for $1.40 each and [#permalink] New post  26 May 2017, 10:49
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A certain vegetable stand sold potatoes for $1.40 each and onions for $1 each. If a customer purchased both potatoes and onions from the stand for a total of $12.60, what total number of potatoes and onions did the customer purchase?

A. 9
B. 10
C. 11
D. 12
E. 13
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pushpitkc
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Re: A certain vegetable stand sold potatoes for $1.40 each and [#permalink] New post  26 May 2017, 12:49
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Let the number of potatoes be x, and the number of onions be y
1.4x + y =12.6
Since, we need to get the exact number of both the vegetables,
the price must end with a .6(which is possible, when x=4)

Now, 5.6 + y = 12.6, which clears the number of onions to be 7.

Total number of onions and potatoes = 4+7 = 11(Option C)
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generis
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A certain vegetable stand sold potatoes for $1.40 each and [#permalink] New post  30 May 2017, 16:08
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Kritesh wrote:
A certain vegetable stand sold potatoes for $1.40 each and onions for $1 each. If a customer purchased both potatoes and onions from the stand for a total of $12.60, what total number of potatoes and onions did the customer purchase?

A. 9
B. 10
C. 11
D. 12
E. 13

The brute force method worked for me here.

Subtract $1.40, price of a potato, as many times as it takes to get to an exact dollar value such that whatever is left is evenly divisible by the price of onions @ $1.00 each.

12.60 - 1.40 = 11.20

11.20 - 1.40 = 9.80

9.80 - 1.40 = 8.40

8.40 - 1.40 = 7.00

That's 4 potatoes.

$7.00 / $1.00 = 7 onions.

Total items: 4 + 7 = 11

Answer C
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ScottTargetTestPrep
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Re: A certain vegetable stand sold potatoes for $1.40 each and [#permalink] New post  01 Jun 2017, 08:51
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Kritesh wrote:
A certain vegetable stand sold potatoes for $1.40 each and onions for $1 each. If a customer purchased both potatoes and onions from the stand for a total of $12.60, what total number of potatoes and onions did the customer purchase?

A. 9
B. 10
C. 11
D. 12
E. 13



We can let n = the number of onions purchased and p = the number of potatoes purchased, and we have:

1.4p + n = 12.6

14p + 10n = 126

10n = 126 - 14p

n = (126 - 14p)/10

n = 14(9 - p)/10

n= 7(9 - p)/5

Since n and p are integers, we see that (9 – p) must be a multiple of 5. This is possible when p = 9, which would make n = 0, or when p = 4, which would make n = 7. Since we know onions were purchased from the vegetable stand, n cannot equal 0. So, the only possible scenario is the purchase of 4 potatoes and 7 onions, totaling 11 vegetables.

Answer: C
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Abhishek009
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Re: A certain vegetable stand sold potatoes for $1.40 each and [#permalink] New post  13 May 2020, 07:39
Kritesh wrote:
A certain vegetable stand sold potatoes for $1.40 each and onions for $1 each. If a customer purchased both potatoes and onions from the stand for a total of $12.60, what total number of potatoes and onions did the customer purchase?

A. 9
B. 10
C. 11
D. 12
E. 13


Check the highlighted part it should click in mind that\( 0.40 * 4 = 1.60\)

Thus, \(1.40 * 4 + 7*1 = 12.60\)

So, the customer purchased \(11 \) Onion and potatoes, Answer must be (C)
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