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Kaps:
is there a rule for this?

I knew that the radius of the circle has to be less than 3, i was stuck between 2 and 2(sqrt(2))!
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fresinha12
Kaps:
is there a rule for this?

I knew that the radius of the circle has to be less than 3, i was stuck between 2 and 2(sqrt(2))!


B.

The lenght of each median of an equilater triangle is (sqrt(3)*side)/2.
For this problem, the centre is the centroid which is always 1/3 the lenght of the median from the base.
So (1/3)(sqrt(3)*side)/2
= (1/3)(sqrt(3)*4*sqrt(3))/2
= 2.

HMTG.
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B)... i divided the triangle in 3 smaller ones. the base is 4sqrt3. the smaller legs that enclose the base are both 1/4sqrt3. so this triangle can again be divided into 2 smaller one with 30:60:90. so its 2sqrt3:2:1/4sqrt3. its 2...



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