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08 Dec 2015, 02:57
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
78% (01:13) correct
22%
(01:31)
wrong
based on 104
sessions
History
Date
Time
Result
Not Attempted Yet
A circular garden is surrounded by a fence of negligible width along the boundary. If the length of the fence is 1/2 of th area of the garden. What is the radius of the circular garden?
A. 1
B. 2
C. 4
D. 8
E. 16
A. 1
B. 2
C. 4
D. 8
E. 16
08 Dec 2015, 03:07
Kudos
Bookmarks
as per the question-- width is negligible
now,
let L be the length of the fence =2pir
L=1/2(pir^2)
pir^2=4pir
r=4
now,
let L be the length of the fence =2pir
L=1/2(pir^2)
pir^2=4pir
r=4
08 Dec 2015, 18:06
Kudos
Bookmarks
Hi All,
This question can be solved algebraically or by TESTing THE ANSWERS.
We're told that the circumference of a circular garden = 1/2 the area of the garden. We're asked for the RADIUS of the garden.
Let's TEST Answer B: 2
IF....Radius = 2
Circumference = 2(pi)R = 4pi
Area = (pi)R^2 = 4pi
This circumference is NOT half the area.
Eliminate Answer B. We need the area to be BIGGER...
Next, Let's TEST Answer D: 8
IF....Radius = 8
Circumference = 2(pi)R = 16pi
Area = (pi)R^2 = 64pi
This circumference is NOT half the area (it's 1/4 of the area).
Eliminate Answer D. We need the area to be SMALLER...
There's only one answer left...
Final Answer:
Here's proof that it's correct:
IF....Radius = 4
Circumference = 2(pi)R = 8pi
Area = (pi)R^2 = 16pi
This circumference IS half the area, so this MUST be the answer.
GMAT assassins aren't born, they're made,
Rich
This question can be solved algebraically or by TESTing THE ANSWERS.
We're told that the circumference of a circular garden = 1/2 the area of the garden. We're asked for the RADIUS of the garden.
Let's TEST Answer B: 2
IF....Radius = 2
Circumference = 2(pi)R = 4pi
Area = (pi)R^2 = 4pi
This circumference is NOT half the area.
Eliminate Answer B. We need the area to be BIGGER...
Next, Let's TEST Answer D: 8
IF....Radius = 8
Circumference = 2(pi)R = 16pi
Area = (pi)R^2 = 64pi
This circumference is NOT half the area (it's 1/4 of the area).
Eliminate Answer D. We need the area to be SMALLER...
There's only one answer left...
Final Answer:
Here's proof that it's correct:
IF....Radius = 4
Circumference = 2(pi)R = 8pi
Area = (pi)R^2 = 16pi
This circumference IS half the area, so this MUST be the answer.
GMAT assassins aren't born, they're made,
Rich
