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15 Jun 2022, 07:30
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
41% (01:50) correct
59%
(01:50)
wrong
based on 17
sessions
History
Date
Time
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Not Attempted Yet
A closed cardboard box is to be designed for packing the cylindrical tube shown above. Will the entire tube fit inside the box?
(1) The empty box contains 3 cubic feet.
(2) The total surface area of the box is 14 square feet.
Are You Up For the Challenge: 700 Level Questions
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16 Jun 2022, 06:51
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(1) The empty box contains 3 cubic feet.
Formula for the volume of this rectangular solid: \(h*l*w = 3\)
Looking at the cylinder, the box will need to be at least 4 in length, 1 in height and 1 in width for it to fit inside. It is impossible that the cylinder fits into any rectangular box with a volume of 3. Even if we looked at placing it diagonally, it wouldn't work.
As the question is: Will the entire tube fit inside the box? And the answer is no, this is SUFFICIENT
(2) The total surface area of the box is 14 square feet.
Formula for the surface area of this rectangular solid: \(2(wl + wh + lh) = 14\) which we can view as \(wl + wh + lh = 7\). Once again, looking at these dimensions and comparing them to the cylinder's length and diameter, it is impossible for the box to contain the cylinder in its entirety .
Once again, we can answer the question with a definite no. SUFFICIENT
Answer D
Formula for the volume of this rectangular solid: \(h*l*w = 3\)
Looking at the cylinder, the box will need to be at least 4 in length, 1 in height and 1 in width for it to fit inside. It is impossible that the cylinder fits into any rectangular box with a volume of 3. Even if we looked at placing it diagonally, it wouldn't work.
As the question is: Will the entire tube fit inside the box? And the answer is no, this is SUFFICIENT
(2) The total surface area of the box is 14 square feet.
Formula for the surface area of this rectangular solid: \(2(wl + wh + lh) = 14\) which we can view as \(wl + wh + lh = 7\). Once again, looking at these dimensions and comparing them to the cylinder's length and diameter, it is impossible for the box to contain the cylinder in its entirety .
Once again, we can answer the question with a definite no. SUFFICIENT
Answer D
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