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# A college reunion gathering had 35 males and 25 females. The average

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Math Expert
Joined: 02 Sep 2009
Posts: 58434
A college reunion gathering had 35 males and 25 females. The average  [#permalink]

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25 Sep 2018, 04:58
00:00

Difficulty:

15% (low)

Question Stats:

87% (01:53) correct 13% (03:24) wrong based on 32 sessions

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A college reunion gathering had 35 males and 25 females. The average (arithmetic mean) age of all of the passed-out students at the gathering was 43 years. If the average age of the males was 45 years, which of the following was the average age, in years, of the females?

(A) 40.2
(B) 41.5
(C) 42.0
(D) 43.5
(E) 44.2

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Joined: 19 Oct 2013
Posts: 516
Location: Kuwait
GPA: 3.2
WE: Engineering (Real Estate)
A college reunion gathering had 35 males and 25 females. The average  [#permalink]

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28 Sep 2018, 15:25
Avg age = (sum)/(total number)
43 = sum/(60)
Sum = 2,580 (for both males and females)

Sum age of males = 35 * 45 =1,575

Sum age of females = 2,580 - 1,575 = 1,005

Avg age of female = 1,005/25 = 40.2

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Joined: 24 Dec 2017
Posts: 185
Location: India
Concentration: Strategy, Real Estate
Schools: Johnson '21
Re: A college reunion gathering had 35 males and 25 females. The average  [#permalink]

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29 Sep 2018, 05:16
Males: 35
Females: 25
Total: 60

Avg(all members) = x/60 = 43
That means the total = 60x43=2580

Avg(Males) = x/35=45
That means the total = 35x45=1575

Find the total age of females in the reunion = 2580-1575 = 1005

Avg(Females) = x/25
=1005/25
=40.2

Hence A
Re: A college reunion gathering had 35 males and 25 females. The average   [#permalink] 29 Sep 2018, 05:16
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